CS 7530 Fall 2021
Assignment 2
10/12/2021
Problem Submission Rules:
1) Detection of plagiarism will result in Failing grade. Students must do this assignment by themselves.
2) After completion, your work must be submitted to an assignment folder in D2L by a corresponding deadline.
3) Late assignments will be accepted up to 24 hours after the due date for 50% credit. Assignments submitted more than 24 hours late will not be accepted for credit.
4) It is much better to submit a partial/failed-attempt solution than none. Include the circumstances of the incompletion in your report.
AES-128 Implementation:
In this assignment, you are going to implement AES-128 including encryption, decryption, and key expansion. The input plaintext is 128-bit, output ciphertext is 128-bit, the input key is also 128-bit and there are 10 rounds.
There is a tremendous amount of information on the web about the AES algorithm. You can find it by searching for “Rijndael” or “Advanced Encryption Standard” on the web. The AES standard is here: AES standard. Any questions about the algorithm can be resolved by looking there. Please also refer to Chapter 6 in our textbook. All the detailed procedures are shown in Chapter 6. The S-box and inverse S-box is on page 155. There are another two sites that are helpful: info on Key Schedule and info on mixColumns. You can use these materials to have a deeper understanding of AES. However, you are NOT supposed to use them. You are expected to code your own implementation.
In the encryption and decryption, please use Electronic Code Book (ECB) mode. That means, encode each block separately, without chaining blocks together. Do not forget to pad the last block of the plaintext if the last block doesn’t have 128 bits.
Your input plaintext should be inside a large file. That file should be a series of lines, each containing a single 128-bit number in hex format. That is, you do not have to worry about encrypting an ASCII file or other file type.
Just to be clear, your input file might start with something like the following lines:
0A935D11496532BC1004865ABDCA4295
00112233445566778899AABBCCDDEEFF
….
You’ll read in a line, converting from Hex to binary for storage into your state array. Apply the AES algorithm to encrypt the string as stored and write out the ciphertext in Hex notation to the output file. When decrypting, you’ll reverse the process. If any line is less than 32 Hex characters (128-bits) pad on the right with zeros. If the line is longer than 32 Hex characters, only consider the first 32. Treat the padded/truncated line as the input; you don’t need to reflect in the output that you padded or truncated the line. Your program should be able to deal with uppercase, lowercase or mixed input.
The key is stored in a separate file, but in the same format. For example, for a 128-bit case, your key file might have the following single line
FFEEDDCCBBAA00998877665544332211
Your program should be able to do each of the following, in accordance with the option command line argument:
1. read in the file of Hex lines and output the corresponding ciphertext in Hex;
2. read in an encrypted file and output the corresponding plaintext.
In the Appendix, I have provided the S-box, inverse S-box, R_con and an AES example from our textbook. You can use it to test code. It includes result after each operation.
Requirements:
1. After the implementation, you will need to write a report to illustrate your code.
2. Given the “plaintext.txt” and “key.txt” as your plaintext and key, use your code to do encryption and output the ciphertext in Hex and save it in a .txt file. Upload the .txt file (your ciphertext) together with the report to D2L.
3. In the report, you will need to demonstrate both the encryption, decryption, and key expansion with the “plaintext.txt” and “key.txt” as your plaintext and key.
4. BONUS: Implement the decryption procedures, read in the encrypted file you got from requirement 2 and output the corresponding plaintext. (Extra 50% points.)
Submission deadline: Sunday 10/24/2021 11:59pm.
Appendix: Test Output for AES-128
S-Box and Inverse S-Box
s_box = (
0x63, 0x7C, 0x77, 0x7B, 0xF2, 0x6B, 0x6F, 0xC5, 0x30, 0x01, 0x67, 0x2B, 0xFE, 0xD7, 0xAB, 0x76,
0xCA, 0x82, 0xC9, 0x7D, 0xFA, 0x59, 0x47, 0xF0, 0xAD, 0xD4, 0xA2, 0xAF, 0x9C, 0xA4, 0x72, 0xC0,
0xB7, 0xFD, 0x93, 0x26, 0x36, 0x3F, 0xF7, 0xCC, 0x34, 0xA5, 0xE5, 0xF1, 0x71, 0xD8, 0x31, 0x15,
0x04, 0xC7, 0x23, 0xC3, 0x18, 0x96, 0x05, 0x9A, 0x07, 0x12, 0x80, 0xE2, 0xEB, 0x27, 0xB2, 0x75,
0x09, 0x83, 0x2C, 0x1A, 0x1B, 0x6E, 0x5A, 0xA0, 0x52, 0x3B, 0xD6, 0xB3, 0x29, 0xE3, 0x2F, 0x84,
0x53, 0xD1, 0x00, 0xED, 0x20, 0xFC, 0xB1, 0x5B, 0x6A, 0xCB, 0xBE, 0x39, 0x4A, 0x4C, 0x58, 0xCF,
0xD0, 0xEF, 0xAA, 0xFB, 0x43, 0x4D, 0x33, 0x85, 0x45, 0xF9, 0x02, 0x7F, 0x50, 0x3C, 0x9F, 0xA8,
0x51, 0xA3, 0x40, 0x8F, 0x92, 0x9D, 0x38, 0xF5, 0xBC, 0xB6, 0xDA, 0x21, 0x10, 0xFF, 0xF3, 0xD2,
0xCD, 0x0C, 0x13, 0xEC, 0x5F, 0x97, 0x44, 0x17, 0xC4, 0xA7, 0x7E, 0x3D, 0x64, 0x5D, 0x19, 0x73,
0x60, 0x81, 0x4F, 0xDC, 0x22, 0x2A, 0x90, 0x88, 0x46, 0xEE, 0xB8, 0x14, 0xDE, 0x5E, 0x0B, 0xDB,
0xE0, 0x32, 0x3A, 0x0A, 0x49, 0x06, 0x24, 0x5C, 0xC2, 0xD3, 0xAC, 0x62, 0x91, 0x95, 0xE4, 0x79,
0xE7, 0xC8, 0x37, 0x6D, 0x8D, 0xD5, 0x4E, 0xA9, 0x6C, 0x56, 0xF4, 0xEA, 0x65, 0x7A, 0xAE, 0x08,
0xBA, 0x78, 0x25, 0x2E, 0x1C, 0xA6, 0xB4, 0xC6, 0xE8, 0xDD, 0x74, 0x1F, 0x4B, 0xBD, 0x8B, 0x8A,
0x70, 0x3E, 0xB5, 0x66, 0x48, 0x03, 0xF6, 0x0E, 0x61, 0x35, 0x57, 0xB9, 0x86, 0xC1, 0x1D, 0x9E,
0xE1, 0xF8, 0x98, 0x11, 0x69, 0xD9, 0x8E, 0x94, 0x9B, 0x1E, 0x87, 0xE9, 0xCE, 0x55, 0x28, 0xDF,
0x8C, 0xA1, 0x89, 0x0D, 0xBF, 0xE6, 0x42, 0x68, 0x41, 0x99, 0x2D, 0x0F, 0xB0, 0x54, 0xBB, 0x16,
)
inv_s_box = (
0x52, 0x09, 0x6A, 0xD5, 0x30, 0x36, 0xA5, 0x38, 0xBF, 0x40, 0xA3, 0x9E, 0x81, 0xF3, 0xD7, 0xFB,
0x7C, 0xE3, 0x39, 0x82, 0x9B, 0x2F, 0xFF, 0x87, 0x34, 0x8E, 0x43, 0x44, 0xC4, 0xDE, 0xE9, 0xCB,
0x54, 0x7B, 0x94, 0x32, 0xA6, 0xC2, 0x23, 0x3D, 0xEE, 0x4C, 0x95, 0x0B, 0x42, 0xFA, 0xC3, 0x4E,
0x08, 0x2E, 0xA1, 0x66, 0x28, 0xD9, 0x24, 0xB2, 0x76, 0x5B, 0xA2, 0x49, 0x6D, 0x8B, 0xD1, 0x25,
0x72, 0xF8, 0xF6, 0x64, 0x86, 0x68, 0x98, 0x16, 0xD4, 0xA4, 0x5C, 0xCC, 0x5D, 0x65, 0xB6, 0x92,
0x6C, 0x70, 0x48, 0x50, 0xFD, 0xED, 0xB9, 0xDA, 0x5E, 0x15, 0x46, 0x57, 0xA7, 0x8D, 0x9D, 0x84,
0x90, 0xD8, 0xAB, 0x00, 0x8C, 0xBC, 0xD3, 0x0A, 0xF7, 0xE4, 0x58, 0x05, 0xB8, 0xB3, 0x45, 0x06,
0xD0, 0x2C, 0x1E, 0x8F, 0xCA, 0x3F, 0x0F, 0x02, 0xC1, 0xAF, 0xBD, 0x03, 0x01, 0x13, 0x8A, 0x6B,
0x3A, 0x91, 0x11, 0x41, 0x4F, 0x67, 0xDC, 0xEA, 0x97, 0xF2, 0xCF, 0xCE, 0xF0, 0xB4, 0xE6, 0x73,
0x96, 0xAC, 0x74, 0x22, 0xE7, 0xAD, 0x35, 0x85, 0xE2, 0xF9, 0x37, 0xE8, 0x1C, 0x75, 0xDF, 0x6E,
0x47, 0xF1, 0x1A, 0x71, 0x1D, 0x29, 0xC5, 0x89, 0x6F, 0xB7, 0x62, 0x0E, 0xAA, 0x18, 0xBE, 0x1B,
0xFC, 0x56, 0x3E, 0x4B, 0xC6, 0xD2, 0x79, 0x20, 0x9A, 0xDB, 0xC0, 0xFE, 0x78, 0xCD, 0x5A, 0xF4,
0x1F, 0xDD, 0xA8, 0x33, 0x88, 0x07, 0xC7, 0x31, 0xB1, 0x12, 0x10, 0x59, 0x27, 0x80, 0xEC, 0x5F,
0x60, 0x51, 0x7F, 0xA9, 0x19, 0xB5, 0x4A, 0x0D, 0x2D, 0xE5, 0x7A, 0x9F, 0x93, 0xC9, 0x9C, 0xEF,
0xA0, 0xE0, 0x3B, 0x4D, 0xAE, 0x2A, 0xF5, 0xB0, 0xC8, 0xEB, 0xBB, 0x3C, 0x83, 0x53, 0x99, 0x61,
0x17, 0x2B, 0x04, 0x7E, 0xBA, 0x77, 0xD6, 0x26, 0xE1, 0x69, 0x14, 0x63, 0x55, 0x21, 0x0C, 0x7D,
)
R_CON:
r_con = (
0x00, 0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40,
0x80, 0x1B, 0x36, 0x6C, 0xD8, 0xAB, 0x4D, 0x9A,
0x2F, 0x5E, 0xBC, 0x63, 0xC6, 0x97, 0x35, 0x6A,
0xD4, 0xB3, 0x7D, 0xFA, 0xEF, 0xC5, 0x91, 0x39,
)
Below is some test output in our textbook. All of this data is in hexadecimal notation. It shows the result of each step of the transformation. You don’t have to produce output that looks like this; it’s here to allow you to see the various transformations so that you can check whether your program is behaving as it should.
AES example: